Well, not me Eddie. I learned all the chords and their inversions in more-or-less the 1-3-5 method. I hadn't heard of this method until now.

I didn't really understand the statement: "so with C being 0, you count up 2 half steps (0, half, one, one and a half, two) and land on the E. "

If C is 0 and you count up 2 half steps you wind up on D, surely? (C=0, first 1/2 step up is C#, 2nd half step up is D)

I think I like my method better...
Trev


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